The correct answer is C
p(X=1)=0.05+0.05+0.10=0.20, p(X=2)=0.05+0.10+0.15=0.30, and p(X=3)=0.15+0.15+0.20=.50. Thus, the mean of X is equal to μ=0.20(1)+0.30(2)+0.50(3)=2.3, and the variance is calculated as 0.20(1-2.3)2+0.30(2-2.3)2+0.50(3-2.3)2=0.61. |